2x^2=210^2

Solution for 2x^2=210^2 equation:

2x^2=210^2

We move all terms to the left:

2x^2-(210^2)=0

We add all the numbers together, and all the variables

2x^2-44100=0

a = 2; b = 0; c = -44100;
Δ = b2-4ac
Δ = 02-4·2·(-44100)
Δ = 352800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352800}=\sqrt{176400*2}=\sqrt{176400}*\sqrt{2}=420\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-420\sqrt{2}}{2*2}=\frac{0-420\sqrt{2}}{4}
=-\frac{420\sqrt{2}}{4}
=-105\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+420\sqrt{2}}{2*2}=\frac{0+420\sqrt{2}}{4}
=\frac{420\sqrt{2}}{4}
=105\sqrt{2}
$